A circle passes through point `(3, sqrt(7/2))` and touches the line-pair `x^2 - y^2 - 2x +1 = 0`. Centre of circle lies inside the circle `x^2 + y^2 - 8x + 10y + 15 = 0`. Coordinates of centre of circle are given by (A) `(4,0)` (B) `(5,0)` (C) `(6,0)` (D) `(0,4)`
A. (4,0)
B. (4,2)
C. (6,0)
D. (7,9)
