When `PbCO_(3)` reacts with dil. HCl (or) dil. `H_(2)SO_(4)` give `CO_(2)` for a moment. Then the reaction slows down. It is because of
A. `PbCO_(3)` does not reacts with dil. HCl (or) `H_(2)SO_(4)` vigorously.
B. Formation of protective layer of `PbCl_(2)` (or) `PbSO_(4)`
C. Dil. HCl (or) `H_(2)SO_(4)` is oxidising `PbSO_(4)`
D. None of the above.
