Compound (A) `C_(10)H_(22)0_(2)` is insoluble in aq. NaOH bu not is `NaHCO_(3)`. Treatment of (A) with DMSO `(CH_(3)-overset(S)overset(||)(S)-CH_(3))` in alkali give (B) `C_(11)H_(14)O_(2)`. Treatment of (A) with strong alkali alone give an isomeric compound (C). When (A) is reflux with HI, `CH_(3)I` is obtained, compound (B) is insoluble in alkali and decolurises `Br_(2)//C Cl_(4)`. (B) on treating with strong base gives (D), an isomer of (B). Ozonolysis (C) of gives (E), `C_(8)H_(8)O` and isomer of vanilline. Ozolysis of (D) gives (F) `C_(9)H_(10)O_(3)`, which is identical with product of methylation of vanilline (4-hydroxy-3-methoxy benzaldehyde).
Compound (E) and (F) are respectively:
A.
B.
C.
D. None of these
