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एक `DeltaABC` में `AD` एक माध्‍यिका है `E` माध्‍यिका का मध्य बिंदु है। यदि `(DeltaBED)` का क्षे0`= 5"सेमी"^(2)` तब `(DeltaABC)` का क्षे0 `=`

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एक `DeltaABC` में `AD` एक माध्‍यिका है `E` माध्‍यिका का मध्य बिंदु है। यदि `(DeltaBED)` का क्षे0`= 5"सेमी"^(2)` तब `(DeltaABC)` का क्षे0 `=`
A. `20 "सेमी"^(2)`
B. `10 "सेमी"^(2)`
C. `60 "सेमी"^(2)`
D. इनमें से कोई नहीं
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Correct Answer - B
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