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In an ionic oxide, oxide ions are arranged in hcp array and positive ion occupy two thirds of octahedral void.

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In an ionic oxide, oxide ions are arranged in hcp array and positive ion occupy two thirds of octahedral void. Suggest the simplest formula assuming metal as M. 

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Analyzing hcp structure 

O2– (in hcp array) = 6 

Octahedral void (in hcp) = 6

M occupies 2/3 rd of octahedral voids = 2/3 x 6 = 4

M4 O6 ⇒ M2 O3

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