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If `f(n)=prod_(i=2)^(n-1)log_i(i+1)`, the value of `sum_(k=1)^100f(2^k)` equals

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in Logarithm by (122k points)
If `f(n)=prod_(i=2)^(n-1)log_i(i+1)`, the value of `sum_(k=1)^100f(2^k)` equals
A. 5010
B. 5050
C. 5100
D. 5049
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1 Answer

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Correct Answer - B
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