Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
68 views
in Mathematics by (122k points)
परवलय का अक्ष y = x है तथा शीर्ष व नाभि मूल बिन्दु से क्रमश : `sqrt(2)` व `2sqrt(2)` की दुरी पर है |तब परवलय का समीकरण है -
A. `(x-y)^(2) = 8(x+y-2)`
B. `(x+y)^(2) =2(x+y -2)`
C. `(x-y)^(2) = 4(x+y -2)`
D. `(x+y)^(2) = 2(x-y+2)`

Please log in or register to answer this question.

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...