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+1 vote
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in Factorization by (123k points)
If `sinx+cosecx=2`, then, for all `n in N`, the value of: `sin^nx+cosec^nx=` (a) `2` (b) `2^n` (c) `2^(n-1)` (d) `2^(n-2)`
A. 2
B. `2^n`
C. `2^n-1`
D. `2^n-2`

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