If the volume of spherical ball is increasing at the rate of `4pi" cc/s"`, then the rate of change of its surface area when the volume is 288 `pi` cc is
A. `(4pi)/(3)" cm"^(2)//"sec".`
B. `(2pi)/(3)" cm"^(2)//"sec."`
C. `4pi" cm"^(2)//"sec."`
D. `2pi" cm"^(2)//"sec."`
