Question

The brakes applied to a car produces deceleration of 6 ms^-2 in opposite direction to the motion. If car requires 2 sec. to stop after application of brakes, calculate distance travelled by the car during this time.

Answer 1

Deceleration, a = − 6 ms^-2  

Time, t = 2 sec. 

Distance, s = ? 

Final velocity, v = 0 ms^-1  (car comes to rest.)