Using the equation \(\left(\cfrac{dp}{dT}\right)\) = \(\cfrac{h_{fg}}{T_s(v_g-v_f)}\)
where, hfg = Enthalpy of vapourisation.
Substituting the various values, we get
32 × 103 = \(\cfrac{h_{fg}}{(200+273)(0.1274-0.001157)}\)
hfg = 32 × 103 (200 + 273)(0.1274 – 0.001157) J
= 1910.8 × 103 J/kg = 1910.8 kJ/kg.