Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
3.1k views
in Physics by (47.2k points) 1 flag
closed by

It is required to design an air-conditioning plant for a small office room for following winter conditions : 

Outdoor conditions ...... 14ºC DBT and 10ºC WBT 

Required conditions ...... 20ºC DBT and 60% R.H. 

mount of air circulation ...... 0.30 m3/min./person. 

Seating capacity of office ...... 60. 

The required condition is achieved first by heating and then by adiabatic humidifying. 

Determine the following : 

(i) Heating capacity of the coil in kW and the surface temperature required if the by pass factor of coil is 0.4. 

(ii) The capacity of the humidifier. 

Solve the problem by using psychrometric chart.

1 Answer

+1 vote
by (41.5k points)
selected by
 
Best answer
  • Locate the points ‘1’ and ‘3’ on the psychrometric chart. 
  • Draw a constant enthalpy line through ‘3’ and constant specific humidity line through ‘1’.
  • Locate the point ‘2’ where the above two lines intersect.

From the psychrometric chart : 

h1 = 29.3 kJ/kg, h2 = h3 = 42.3 kJ/kg

tdb2 = 24.5ºC, vs1 = 0.817 m3/kg

The mass of air circulated per minute,

ma\(\cfrac{0.30\times60}{0.817}\) = 22.03 kg/min

(i) Heating capacity of the heating coil

= ma(h2 – h1) = 22.03 (42.3 – 29.3) = 286.4 kJ/min. 

= 4.77 kJ/s or 4.77 kW.

The by-pass factor (BF) of heating coil is given by :

tdb4 (coil surface temperature) = 32.8ºC. 

(ii) The capacity of the humidifier

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...