- Locate the points ‘1’ and ‘3’ on the psychrometric chart.
- Draw a constant enthalpy line through ‘3’ and constant specific humidity line through ‘1’.
- Locate the point ‘2’ where the above two lines intersect.

From the psychrometric chart :
h1 = 29.3 kJ/kg, h2 = h3 = 42.3 kJ/kg
tdb2 = 24.5ºC, vs1 = 0.817 m3/kg
The mass of air circulated per minute,
ma = \(\cfrac{0.30\times60}{0.817}\) = 22.03 kg/min
(i) Heating capacity of the heating coil
= ma(h2 – h1) = 22.03 (42.3 – 29.3) = 286.4 kJ/min.
= 4.77 kJ/s or 4.77 kW.
The by-pass factor (BF) of heating coil is given by :

tdb4 (coil surface temperature) = 32.8ºC.
(ii) The capacity of the humidifier
