Iodobenzene( `C_(6)H_(5)I`) is prepared from aniline (`C_(6)H_(5)NH_(2)`) in a two step process as shown below
`C_(6)H_(5)NH_(2)` + `HNO_(3)` + HCl `to` `C_(6)H_(5)N_(2)""^(+)Cl^(-) +2H_(2)O`
`C_(6)H_(5)N_(2) ^(+)Cl^(-) + Kl to C_(6)H_(5)I + N_(2) + KCl`
In an actual preparation 9.30 g of analine was converted to 16.32 g of iodobenzene . The percentage yeild of iodobenzene is : (I = 127 )
A. `8%`
B. `50%`
C. `75%`
D. `80%`
