An unknown chlorohydrocarbon has 3.55% of chlorine. If each molecule of the hydrocarbon has one chlorine atom only, chlorine atoms present in 1 g of chlorohydrocarbon are :
(Atomic wt. of C1 = 35.5 u, Avogador constant `= 6.023xx10^(23) mol^(-1)) `
A. `6.023xx10^(21)`
B. `6.023xx10^(23)`
C. `6.023xx10^(20)`
D. `6.023xx10^(9)`