The reaction of compounf P with `CH_(3)MgBr` (excess) in `(C_(2)H_(5)_(2)O` followed by addition of `H_(2)O` give Q the compound Q on treatment with `H_(2)SO_(4)` at `0^(@)` C gives R. the reaaction of R with `CH_(3) COCl` in the presence of anhydrous `AlCl_(3)` in `CH_(2)Cl_(2)` followed by treatment with `H_(2)O` "produces compound S`. [Et in compound P is ethyl group]
The reaction, Q to R and R TO S, are
A.
B.
C.
D.
