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in Chemistry by (75.1k points)
`HBr` reacts with `CH_(2)=CH-OCH_(3)` under anhydrous conditions at room temperature to give:
A. `CH_3CHO and CH_3Br`
B. `BrCH_2CHO and CH_3Br`
C. `BrCH_2-CH_2-OCH_3`
D. `H_3C-CHBr-OCH_3`

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