An `AC` voltage source `V=V_0siomegat`is connected across resistance `R` and capacitance `C` as shown in figureure. It is given that `R=1/omegaC`. The peak current is `I_0`. If the angular frequency of the voltage source is changed to `omega/sqrt3,` then the new peak current in the circuit is
.
A. `(I_(0))/(2)`
B. `(I_(0))/(sqrt2)`
C. `(I_(0))/(sqrt3)`
D. `(I_(0))/(3)`