Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
228 views
in Physics by (75.1k points)
A parallel plate capacitor is charged up to a potential of 300 volts. Area of the plates is `100 cm^(2)` and spacing between them is 2 cm. If the plates are moved apart to a distance of 2.5 cm without disconnected the power source, then `(in_(0)=9xx10^(-12)C^(2)N^(-1)m^(-2))`:
(i) Electric field inside the capacitor when distance when distance is 2.5 cm :
A. `303.75xx10^(-9) J`
B. `-1215xx10^(-10)J`
C. `5.06xx10^(-8)J`
D. `303.75 xx 10^(-9)J`

Please log in or register to answer this question.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...