Question

Let f(x) = secx + tanx, g(x) = tanx/(1 - sec(x))

Statement - 1 g is an odd function 

Statement - 2 f is neither an odd function nor an even function 

(a) Statement 1 is true 

(b) Statement 2 is true 

(c) 1 and 2 both are true 

(d) 1 and 2 both are false

Answer 1

The correct option (c) 1 and 2 both are true

Explanation:

f(–x) = sec (–x) + tan (–x) 

= sec x – tan x 

≠ – f(x) 

∴ f is neither odd function nor an even function. 

g(–x) = –g(x) 

∴ g is an odd function.