Question

What mass of 68% H₂SO₄ will be required to make 2L solution of 5M molarity? 

Answer 1

Mass of H₂SO₄ in 5M solution = M x MM x V (L) = 5 x 98 x 2 = 980 g 68 g of H₂SO₄ = 100 g of 68% H₂SO₄

980 g of H₂SO₄ = 100 x 980 /68 = 1441.18 g of 68% H₂SO₄