Here b = 120 mm, d = 180 mm, I = \(\frac1{12}\) bd3 , ymax = \(\frac d2\)
∴ Moment carrying capacity of the section
= fper × Z
= 10 × 648000 N-mm
(i) Let maximum udl beam can carry be w/metre length as shown in Fig.
In this case, we know that maximum moment occurs at mid span and is equal to Mmax = \(\frac{wL^2}8\)
Equating it to moment carrying capacity, we get,
(ii) Concentrated load at distance 1 m from the support be P kN. Referring to Fig.
Equating it to moment carrying capacity, we get
\(\frac{2P}3\) × 106 = 10 × 648000
∴ P = 9.72 kN-m.