Question

Calculate the number of sulphate ions in 100 mL of 0.001 M ammonium sulphate solution.

(a)  6.022 x 10^-19

(b)  6.022 x 10¹⁹

(c) 6.022 x 10²⁰

(d) 6.022 x 10^-20

Answer 1

Correct option  (b) 6.022 x 10¹⁹

No of moles of (NH₄)₂ SO₄ = molarity x vol(L)

= 0.001 x 0.1 = 0.0001

:. No of SO^2-₄  ions = 0.0001 x 6.022 x 10²³ = 6.022 x 10¹⁹