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The largest number which divides 62, 132 and 237 to leave the same remainder in each case is:  (A) 51 

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The largest number which divides 62, 132 and 237 to leave the same remainder in each case is: 

(A) 51 

(B) 35 

(C) 8 

(D) 53

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1 Answer

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(B) 35

132 - 62 = 70 

237 - 132 = 105 

237 - 62 = 175 

HCF = 35

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