Question

ABC is a right angled triangle, right angled at B. If D and E are points on side AB such that AD = DE = EB, then the value of 

\(\frac{AC^2-EC^2}{DC^2 - BC^2}\) is

1. 3 /1 

2. 5 /2 

3. 9 /4 

4. 2 /1

Answer 1

4. 2 /1

\(\frac{AC^2-EC^2}{DC^2 - BC^2}\)

\(\frac{9x^2+BC^2-(x^2+BC^2)}{4x^2+BC^2-BC^2}\) = \(\frac{8x^2}{4x^2}=\frac{2}{1}\)