In an isosceles right angled triangle, the two sides on the right angle are equal.
Let the equal side be a
Hence, hypotenuse of the isosceles right angled triangle of side \(a = \sqrt{a^2 + a^2} = \sqrt2 a\)
In the isosceles right triangle, the base and height = a
Hence, area of the triangle = \(\frac{1}{2} \times base \times height\)
\(\frac{1}{2} \times a \times a = 392 cm^2\)
\(a^2 = 784\)
a = 28 cm
And the hypotenuse = \(\sqrt2 a = 28 \sqrt2 cm\)