(1) As we have given that the internuclear axis in the z-direction
\(\therefore \) So, overlap of 2Px orbital always form \(\pi\)-bond and we know that \(\pi\)-bond is weaker than \(\sigma \) bonds
(2) Yes - Linear combination of two 2Pz orbital formed one, \(\sigma \) bonding molecular orbital and one \(\sigma \) anti bonding molecular orbital .
(3) As given, The internuclear axis in z-direction
So, 2Px always form \(\pi\) bonding and \(\pi\) anti bonding molecular orbital. as we know \(\pi\) - bonds are not symmetrical around \(\sigma \) bond or internuclear axis. so it is also correct statement.
(4)

energy of 2s and 2Pz orbitals are almost same so that they can overlap effectively and form bonding orbitals.
Hence, option (2), (3) and (4) are correct statement.