Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.7k views
in Physics by (15 points)
19. A concave mirror has a focal length of \( 4 cm \) and an object \( 2 cm \) tall is placed \( 9 cm \) away from it. Find the nature, position and size of the image formed. 20. When an object is placed \( 20 cm \) from a concave mirror, a real image magnified three times is formed. Find: (a) the focal length of the mirror.

Please log in or register to answer this question.

1 Answer

0 votes
by (15 points)

f = -4 cm, ho = 2 cm, u = -9 cm

Using mirror formula

\({1\over f} = {1\over v}+{1\over u} \)

\({1\over -4} = {1\over v}+{1\over -9}\)

\({1\over v} = {1\over 9}-{1\over 4}\)

\({1\over v} = {4-9\over 36}\)

\(v=-7.2 cm\)

Now, using the magnification formula, we get 

\(m = {h_{i}\over h_{o}}= -{v\over u}\)

\({h_{i}\over h_{o}} = -{(-7.2)\over -9}\)

\({h_{i}\over 2} = -{(-7.2)\over -9}\)

\(h_{i}={{2\times(-7.2)}\over -9}\)

\(h_{i}= -1.6cm\)

Thus, the height of the image '\(h_{i}\)' is 1.6 cm.

Thus, the image is real, inverted and small in size.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...