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Ka for CH3COOH at 25ºC is 1.754 × 10^–5 . At 50ºC, Ka is 1.633 × 10^–5 What will be value of Δ Sº for the

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Ka for CH3COOH at 25ºC is 1.754 × 10–5 . At 50ºC, Ka is 1.633 × 10–5 What will be value of Δ Sº for the ionisation of CH3COOH ?

(A)   –94.44 J/mole K 

(B)   –96.66 J/mole K

(C)   –96.44 J/mole K

(D)  –90.44 J/mole K

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Correct option (C) –96.44 J/mole K

Explanation:

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