माना पहली सम संख्या = x
तथा दूसरी सम संख्या = x + 2
प्रश्नानुसार,
(x)2 + (x + 2)2 = 340
x2 + x2 + 4 + 4x – 340 = 0
2x2 + 4x – 336 = 0
2(x2 + 2x – 168) = 0
x2 + 2x – 168 = 0
x2 + 14x – 12x – 168 = 0
x (x + 14) – 12(x + 14) = 0.
(x + 14)(x – 12) = 0
(x + 14)(x – 12) = 0
यदि x + 14 = 0, तब x = – 14 (अमान्य)
तथा यदि x – 12 = 0, तब x = 12
अतः दो सम संख्याएं x = 12
तथा x + 2 = 12 + 2 = 14
