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If z = x + iy is a complex number satisfies\(\bar Z\)=iz2+z-i then sum of square of all values of z satisfies given equation is

(1) 1

(2) 2

(3) 3

(4) 4

1 Answer

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Best answer

Correct option is (1) 1

sum of square is = (i)2 + (1)2 + (-1)2 = 1

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