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Equation of circle (x-1)^2+(y-2)^2 = 5 drawing 2 tangents at (0,0) & (1+√5,0) they intersect. Find area of that triangle.

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Equation of circle (x-1)2+(y-2)2 = 5 drawing 2 tangents at (0,0) & (1+√5,0) they intersect. Find area of that triangle.

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Correct answer is \(\frac{1+\sqrt{5}}{4}\)

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