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0 votes
1.6k views
in Physics by (235 points)
Question: A radioactive element has a half life of 200 days. The percentage of original activity remaining after 83 days is (Nearest integer) (Given : antilog \( 0.125=1.333 \), antilog \( 0.693=4.93) \)

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1 Answer

0 votes
by (15 points)
N=Nºe^-lambda×t

N/Nº=e^(0.693/200)×83
by (235 points)
I want the calculation using the above values

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