lim(x→π/2)(tan^2x(2 sin^2x + 3sin x + 4)^1/2) - (sin^2x + 6sin x + 2)^1/2)) is equal to

Question

 \(\lim\limits(x\to \pi/2)\)(tan²x(2sin²x + 3 sin x + 4)^1/2 - (sin²x + 6 sin x + 2)^1/2) is equal to

(A) 1/12

(B) -1/18

(C) -1/12

(D) -1/6

Answer 1

Correct option is (A) 1/12