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Let a circle C touch the lines L1 : 4x – 3y + K1 = 0 and L2 : 4x – 3y + K2 = 0, K1 , K2 \(\in\) R. If a line passing through the centre of the circle C intersects L1 at (–1, 2) and L2 at (3, – 6), then the equation of the circle C is 

(A) (x – 1)2 + (y – 2)2 = 4 

(B) (x + 1)2 + (y – 2)2 = 4 

(C) (x – 1)2 + (y + 2)2 = 16 

(D) (x – 1)2 + (y – 2)2 = 16

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Correct option is (C) (x – 1)2 + (y + 2)2 = 16 

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