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50 mL of 0.1 M CH3COOH is being titrated against 0.1 M NaOH. When 25 mL of NaOH has been added, the pH of the solution will be ________ × 10–2 . (Nearest integer) 

(Given : pKa (CH3COOH) = 4.76) 

log 2 = 0.30

log 3 = 0.48 

log 5 = 0.69 

log 7 = 0.84 

log 11 = 1.04

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Best answer

Correct answer is 476

Moles of CH3COOH = 5 m mole 

moles of NaOH = 2.5 m mole

 

so buffer is formed

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