If the inverse trigonometric functions take principal values, then cos^-1(3/10(tan^-1(4/3))+2/5 sin(tan^-1(4/3)))

If the inverse trigonometric functions take principal values, then \(cos^{-1}(\frac3{10}(tan^{-1}(\frac43))+\frac25(tan^{-1}(\frac43)))\) is equal to:

(A) 0

(B) π/4

(D) π/6

If the inverse trigonometric functions take principal values, then cos^-1(3/10(tan^-1(4/3))+2/5 sin(tan^-1(4/3)))

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