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The cut-off voltage of the diodes (shown in figure) in forward bias is 0.6 V. The current through the

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The cut-off voltage of the diodes (shown in figure) in forward bias is 0.6 V. The current through the resister of 40 Ω is _____ mA.

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Correct answer is 4

1 – I(60) – 0.6 – I (40) = 0

0.4/100 = I

I = 4 mA

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