Question

A metallic conductor of length 1m rotates in a vertical plane parallel to east-west direction about one of its end with angular velocity 5 rad/s. If the horizontal component of earth's magnetic field is 0.2 × 10^–4 T, then emf induced between the two ends of the conductor is : 

(A) 5µV 

(B) 50µV 

(C) 5mV 

(D) 50mV

Answer 1

Correct option is (B) 50µV

emf induced between the two end  = \(\frac{B_H\omega t^2}2\) 

\(\frac{0.2\times10^{-4}\times5\times1}{2}\) = 0.5 x 10^-4 = 50 x 10^-6 V

 = 50µV