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 \(∫\cfrac{(x^2+1)e^x}{(x+1)^2}\)  dx = f(x)e+ c, Where C is a constant, then \(\frac{d^3f}{dx^3}\)  at x = 1 ​​​​​​is equal to : 

(A) -3/4 

(B) 3/4 

(C) -3/2

(D) 3/2

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