Question

A ball is projected with a velocity, 10 ms^–1, at an angle of 60° with the vertical direction. Its speed at the highest point of its trajectory will be: 

(1) 5√3 ms^-1

(2) 5 ms^–1 

(3) 10 ms^–1 

(4) Zero

Answer 1

Correct option is (1) 5√3 ms^-1

At highest point only horizontal component of velocity remains 

⇒ u_x = u cosq