Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
4.6k views
in Chemistry by (44.1k points)
closed by

Given below are two statements: -

Statement I:

The boiling points of aldehydes and ketones are higher than hydrocarbons of comparable molecular masses because of weak molecular association in aldehydes and ketones due to dipole - dipole interactions.

Statements II:

The boiling points aldehydes and ketones are lower than the alcohols of similar molecular masses due to the absence of H-bonding.

In the light of the statements, choose the most appropriate answer from the options given below:

(1) Both statements I and statements II are incorrect.

(2) Statement I is correct but statements II is incorrect

(3) Statements I is incorrect but statements II is correct.

(4) Both statements I and statements li are correct.

1 Answer

+1 vote
by (45.2k points)
selected by
 
Best answer

(4) Both statements I and statements li are correct.

Boiling point of comparable molecular mass molecules

R-OH - > Aldehyde - Ketone  > Alkane

H-bonding Dipole-dipole interaction Non-polar

strong molecular (weak molecular association) 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...