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एक वर्ग बनाइए जिसका विकर्ण 6.4 सेमी हो।

[संकेत – वर्ग के विकर्ण एक दूसरे को समकोण पर समविभाजित करते हैं।]

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रचना :

  1. सर्वप्रथम AC = 6.4 सेमी का रेखाखंड खींचा।
  2. फिर AC का लम्बार्द्धक खींचा जो AC को 0 पर काटता है।
  3. बिन्दु 0 से विकर्ण का आधा 64 = 3.2 सेमी के चाप दोनों ओर लगाए जो लम्बार्द्धक को क्रमशः बिन्दु B तथा D पर काटते हैं ।
  4. AB, BC, CD तथा DA को मिलाया ।

अतः ABCD अभीष्ट वर्ग है ।

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