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एक 3 सेमी माप के रेखाखण्ड AB के सिरे A पर लम्ब AC = 3 सेमी खींचिए। बिन्दुओं B,C को मिलाइए। कोणों को मापकर सत्यापित कीजिए कि ∠ABC = ∠ACB = 45°

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सत्यापन-चूँकि दो समान भुजाओं के सामने के कोण बराबर होते हैं। अतः CA ∠ABC = ∠ACB

हम जानते हैं कि त्रिभुज के तीनों कोणों का योग = 180°

∴ ∠ABC + ∠ ACB + ∠CBA = 180°

∠ABC + ∠ABC + 90° = 180°

2 ∠ABC = 180° – 90°

∠ABC = 90/2 = 45°

∠ABC = 2 ACB = 45°

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