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In the shown AC circuit in figure, phase difference between current I1 and I2 is

(A) \(\frac\pi2 - tan^{-1} \frac{X_L}{R}\)

(B) \(tan^{-1} \frac{X_L - X_C}{R}\)

(C) \(\frac\pi2 + tan^{-1} \frac{X_L}{R}\)

(D) \(tan^{-1} \frac{X_L - X_C}{R} + \frac\pi2\)

1 Answer

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Best answer

Correct option is (A) \(\frac\pi2 - tan^{-1} \frac{X_L}{R}\) 

Let us consider mesh (1);

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