Question

Mean & variance of a binomial probability distribution satisfies the relation 

Mean + variance = 24

Mean x variance = 128

Probability of getting 1 or 2 success in this distribution is.

(1) \(\frac{31}{2^{28}}\)

(2) \(\frac{33}{2^{28}}\)

(3) \(\frac{33}{2^{32}}\)

(4) \(\frac{17}{2^{28}}\)

Answer 1

Correct option is (2) \(\frac{33}{2^{28}}\)