Correct answer is 2.00
K4[Fe(CN6)] is diamagnetic
K3[Cu(CN)4] is diamagnetic
K2[Cu(CN)4] is paramagnetic as it has one unpaired electron
K3[Fe(F6)] is paramagnetic as it has 5 unpaired electrons.
Therefore, only 2 compounds K4[Fe(CN6)] and K3[Cu(CN)4] are diamagnetic