Arrange following according to decreasing order of energy (a) n = 3, I = 0, m = 0, s = -1/2

Question

Arrange following according to decreasing order of energy

(a) n = 3, I = 0, m = 0, s = \(-\frac12\)

(b) n = 3, I = 1, m = -1, s = \(+\frac12\)

(c) n = 3, I = 2, m = +2, s = \(+\frac12\)

(d) n = 4, I = 0, m = 0, s = \(+\frac12\)

(1) c > d > b > a

(2) d > c > b > a

(3) a > b > c > d

(4) c > d > a > b

Answer 1

Correct option is (1) c > d > b > a

Energy depends on (n + 1) so correct order ⇒ 3d > 4s > 3p > 3s