Question

A transverse wave is represented by y = 2sin (ωt - kx) cm. The value of wavelength (in cm) for which the wave velocity becomes equal to the maximum particle velocity, will be ;

(A) 4π

(B) 2π

(C) π

(D) 2

Answer 1

Correct option is (A) 4π

y = 2 sin (ωt – kx)

Maximum particle velocity = A ω

Wave velocity = \(\frac\omega k\)