Question

Three point charges of magnitude 5µC, 0.16µC and 0.3µC are located at the vertices A, B, C of a right angled triangle whose sides are AB = 3cm, BC 3√2  cm and CA = 3 cm and point A is the right angle corner. Charge at point A experiences _______ N of electrostatic force due to the other two charges.

Answer 1

Correct answer is 17 N

Comments

But according to the vector addittion the formula is √(F1)^2+(F2)^2+2F1F2costhits

---

cos 90° = 0
Then
R = √(F^2 1 + F ^2 2 + 2F1 f2 cos 90°)
R = √(F^2 1 + F^2 2 + 0)

---

can u explain how u got the distance between 2 charges as 9 x 10^-4

---

Distance diya va hai 3cm uska square karega to 9×10^-4 hi aayega na