Question

In a series LR circuit X_L = R and power factor of the circuit is P₁. When capacitor with capacitance C such that X_L = X_C is put in series, the power factor becomes P₂. The ratio \(\frac{P_1}{P_2}\) is

(A) \(\frac 12\)

(B) \(\frac 1{\sqrt 2}\)

(C) \(\frac{\sqrt3}{\sqrt 2}\)

(D) 2:1

Answer 1

Correct option is (B) \(\frac 1{\sqrt 2}\) 

In case of L-R circuit

In case of L-C-R circuit